RC time constant calculator
Work out the time constant of a resistor and capacitor, the −3 dB corner it puts on a low-pass filter, and how long a step takes to settle.
Time constant
15.92 µs
Corner frequency (−3 dB)
9.997 kHz
Settles within 0.01 %
146.6 µs, or 9.21 time constants
After one time constant
63.2 % of the way there
τ = R × C · f₋₃dB = 1 ÷ (2π × R × C) · t = −ln(accuracy ÷ 100) × R × C
A resistor feeding a capacitor has one number that governs everything it does: the time constant, the resistance times the capacitance. It sets how fast the capacitor charges, where the circuit stops passing signal, and how long you have to wait before a reading means anything. This works out all three from the two component values.
How it is calculated
τ = R × C · f₋₃dB = 1 ÷ (2π × R × C) · t = −ln(accuracy ÷ 100) × R × C
The step response is 1 − e^(−t/RC), so the capacitor covers the same fraction of the remaining distance in every time constant: 63.2 % after one, 99.3 % after five. It never quite arrives, which is why settling is quoted to an accuracy rather than as a finish line.
Questions people ask
- How long until the capacitor is charged?
- It never finishes, so the question has to be asked with a tolerance attached. Each time constant closes 63.2 % of whatever distance is left: one gets you to 63.2 %, five to 99.3 %, and 9.2 of them to within 0.01 % of the final value. Pick the accuracy your circuit actually needs and read the time off above.
- Why is the corner not where the signal stops?
- Because a single RC is a gentle filter. The corner frequency is where the output has fallen to −3 dB, about 71 % of the input, and beyond it the response only falls by a factor of ten per decade. Signal well above the corner is attenuated, not removed.
- Does swapping the resistor and capacitor change anything?
- Not the time constant, and not the corner. Doubling the resistance and halving the capacitance leaves both untouched. What it changes is everything around them: the current drawn, the impedance the circuit presents, and how much the following stage loads it.
- Why does my 10 kHz filter not come out at 10 kHz?
- Because the parts are rounded before the maths is. The bulletin behind this page pairs 10 kΩ with 1592 pF and calls it a 10 kHz filter; work it through exactly and the corner lands at 9.997 kHz. Nothing is wrong — capacitors come in the values they come in, and a corner three parts in ten thousand off nominal is far inside the tolerance of the capacitor itself.
- Is filtering worth the wait?
- That is the trade the bulletin behind this page was written about. Narrowing the bandwidth by a factor of a hundred cuts broadband noise by ten, because noise adds as the square root of the bandwidth — but the settling time grows in step. In fast measurement work that penalty is often the binding constraint.
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